Calculate the enthalpy of reaction (ΔH rxn ) for the following reaction:
Fe 2 O 3 (s) + 3 CO(g) → 2 Fe(s) + 3 CO 2 (g)
Given:
4 Fe(s) + 3 O 2 (g) → 2 Fe 2 O 3 (s) ΔH = –1648 kJ
2 CO 2 (g) → 2 CO(g) + O2(g) ΔH = +565.4 kJ
Lets number the reaction as 0, 1, 2 from top to bottom
required reaction should be written in terms of other reaction
This is Hess Law
required reaction can be written as:
reaction 0 = -0.5 * (reaction 1) -1.5 * (reaction 2)
So, deltaHo rxn for required reaction will be:
deltaHo rxn = -0.5 * deltaHo rxn(reaction 1) -1.5 * deltaHo rxn(reaction 2)
= -0.5 * (-1648.0) -1.5 * (565.4)
= -24.1 KJ
Answer: -24.1 KJ
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