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Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are...

Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 26.0 g of aluminum and 31.0 g of chlorine gas.

A) If you had excess chlorine, how many moles of of aluminum chloride could be produced from 26.0 g of aluminum?

B)If you had excess aluminum, how many moles of aluminum chloride could be produced from 31.0 g of chlorine gas, Cl2?

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