Question

In the acetylene torch, acetylene gas (C2H2) burns in oxygen to produce carbon dioxide and water.
2C2H2(g)+5O2(g)→4CO2(g)+2H2O(g)

A) How many moles of O2 are needed to react with 3.00 moles C2H2?

B)How many moles of CO2 are produced when 3.2 moles C2H2 reacts?

C)How many moles of C2H2 are required to produce 0.58 mole H2O?

D)How many moles of CO2 are produced from 0.200 mole O2?

Answer 1

2C2H2(g)+5O2(g)→4CO2(g)+2H2O(g)

A) 2 moles C2H2 reqyure 5 moles O2

3.0 moles C2H2 require 3.0 x 5 / 2 = 7.5 moles O2

moles of O2 required = 7.5

B) 2 moles C2H2 produce 4 moles CO2

3.2 moles CH2 produce 3.2 x 4 / 2 = 6.4

moles of CO2 produced = 6.4

C) 2 moles H2O require 2 moles C2H2

0.58 moles H2O require 0.58 x 2 / 2 = 0.58 moles C2H2

moles C2H2 require = 0.58

D) 5 moles O2 produce 4 moles CO2

0.20 moles O2 produce 0.20 x 4 / 5 = 0.16

moles CO2 produced = 0.16