Question

titration of a 12mL solution of HCl requires 22.4 mL of .12 M NaOH? what is the molarity of the HCl solution?

Answer 1

write the balanced equation

   HCl + NaOH ---> NaCl+ H2O

Molarity = from the balanced equation 1mole Hcl requires to neutralize 1 mole HCl

first calculate number of moles of NaOH from given data

number of moles =molarity *volume in litres     since 22.4ml= 22.4*1000=0.0224L

moles of NaOH used= 0.12*0.0224=0.002688 moles of NaOH

since 1mole NaOH neutralizes 1 mole HCl

0.002688mole NaOH neutralizes ? moles HCl

=0.002688mole NaOH *1 mole HCl/1mole NaOH

moles of HCl=0.002688mole

since molarity =moles/volume (L)

Molarity(HCL)=0.002688mole/0.012=0.224M HCl