Question

I need to know the reducible representations of cH2cl2

Answer 1

Point group for CH₂Cl₂ is C_2V.

Now consider the table of C_2V to deduce reducible representation:

C2V	E	C2	σ v (xz)	σ’v (yz)
A1	1	1	1	1	Z	x2, y2,z2
A2	1	1	-1	-1	Rz	xy
B1	1	-1	1	-1	x, Ry	xz
B2	1	-1	-1	1	y, Rx	yz

In E operation for CH₂Cl₂ = 1+1+1+1 = 4

In C₂ operation of CH₂Cl₂ all four bonds moves, thus; 1-1+1-1=0

In σ _v operations, two bonds move and two does not move, thus; 1+1 = 2

Therefore, Reducible representation is:

C2V	E	C2	σ v (xz)	σ’v (yz)
Γσ	4	0	2	2

answered by: anonymous