A system expands from a volume of 1.00 L to 2.00 L against a constant external pressure of 1.00 atm. What is the work (w) done by the system? (1 L·atm = 101.3 J)
volume change = V1 - V1
= 2 - 1
= 1.00 L
external pressure = 1.00 atm
work = - p dV
= - 1 x 1
= - 1 L.atm
work done by system = -101.3 J
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