Question

Hello i am having a hard time solving the following physical chemistry question: Estimate the number of photos generated by your favorite FM Station that is assumed to ave a power of 45kW. (If you do not listen to any FM station, assume the transmission frequencey of 98.4 MHz). Also comment on whether photons will be emitted from an AM broadcast.

Please include step by step. Thank you!

Answer 1

POWER = energy per time

P = 45 kW = 45*10^3 W = 45*10^3 J/s

v = frequency in Hz = 98.4 MHz = 98.4*10^6 Hz

then...

get Energy from

E = hv

h = planck constant = 6.626*10^-34

E = (6.626*10^-34 )(98.4*10^6) = 6.5199*10^-26 J/photon

now...

Nphoton flow = Etota / Ephoton = (45*10^3) / (6.5199*10^-26) = 6.9019*10^29 photons per second

change to mol of photon --> (6.9019*10^29 )/(6.022*10^23) = 1146114.2 mol of photon per second

assume per hour --> 1146114.2/3600 = 318.3 mol of photon per hour