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what is molarity of .115m hydrochloric acid reacts completely with .125g of sodium carbonate(105.99 g/mol)

what is molarity of .115m hydrochloric acid reacts completely with .125g of sodium carbonate(105.99 g/mol)

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Answer #1

      2HCl (aq)+ Na2CO3(aq) ----------------> 2NaCl (aq) + CO2(g) + H2O(l)

   no of moles of Na2CO3 = W/G.M.Wt

                                          = 0.125/105.99   = 0.00118 moles

1 moles of Na2CO3 react with 2 moles of HCl

0.00118 moles of Na2Co3 react with = 2*0.00118/1   = 0.00236 moles of HCl

molarity = no of moles * volume in L

0.115        = 0.00236* volume in L

volume in L = 0.115/0.00236   = 48.73L >>>>answer

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