Consider the following equilibrium in a sealed reactor:
C2H4(g)+ 5O2 --> 4CO2(g)+ 2H2O(g)
Predict the effect of each of the following changes on the equilibrium position of the reaction. The reaction will either shift to the left (forming more reactants), stay the same, or shift to the right (forming more products).
a) the partial pressure of O2(g)
b) The volume of the reactor is double
c) A total of 10.0 bar of Ar gas is added to the reactor.
The equillibrium position of the reaction changes according to the Le chatelier's principle , if any reaction conditions are changed.
a) The partial pressure of O2 :
If increased , the equillibrium shifts to right , if decreased the equillibrium shifts to left.
b) The volume is doubled :
The pressure of the reaction is decreased. But since the pressure is same on both the sides , the equillibrium stays the same.
c) A total of 10.0 bar of Ar is added to the reactor
When the noble gas is added , it does not react , but increases the pressure in the reaction. Since the pressure is same on both the sides , the equillibrium stays the same.
Get Answers For Free
Most questions answered within 1 hours.