Question

The amount of anhydrous magnesium sulfate used is determined by?' a. seeing MgSO4 -7 H2O crystals...

The amount of anhydrous magnesium sulfate used is determined by?'

a. seeing MgSO4 -7 H2O crystals form

b. seeing magnesium sulfate dissolve

c. seeing excess anhydrous magnesium sulfate powder

d. the stoichiometry of magnesium sulfate to water forming MgSO4 -7 H2O

e. adding enough magnesium sulfate to cover the liquid

Homework Answers

Answer #1

Ans :- Option (d) i.e. "the stoichiometry of magnesium sulfate to water forming MgSO4 -7 H2O" is the correct answer.

Explanation :-

The amount of anhydrous magnesium sulfate i.e. MgSO4 used is determined by using stoichiometry of magnesium sulphate to water molecules forming MgSO4.7H2O as :

MgSO4(s) + 7H2O (l) -----> MgSO4.7H2O(s) (hydrated salt)

From this equation, 7 mole of H2O are absorbed by 1 mole of MgSO4 . Due to this stochiometric relationship we can find number of H2O molecules that are absorbed by MgSO4 .

Hence option (d) is the correct answer.

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