The amount of anhydrous magnesium sulfate used is determined by?'
a. seeing MgSO4 -7 H2O crystals form
b. seeing magnesium sulfate dissolve
c. seeing excess anhydrous magnesium sulfate powder
d. the stoichiometry of magnesium sulfate to water forming MgSO4 -7 H2O
e. adding enough magnesium sulfate to cover the liquid
Ans :- Option (d) i.e. "the stoichiometry of magnesium sulfate to water forming MgSO4 -7 H2O" is the correct answer.
Explanation :-
The amount of anhydrous magnesium sulfate i.e. MgSO4 used is determined by using stoichiometry of magnesium sulphate to water molecules forming MgSO4.7H2O as :
MgSO4(s) + 7H2O (l) -----> MgSO4.7H2O(s) (hydrated salt)
From this equation, 7 mole of H2O are absorbed by 1 mole of MgSO4 . Due to this stochiometric relationship we can find number of H2O molecules that are absorbed by MgSO4 .
Hence option (d) is the correct answer.
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