Question

what volume of co2 can be obtained from the decomposition of 250 g of caco3 at stp

Answer 1

Given mass of CaCO3=250 g and molar mass of CaCO3=100 g/mol

Moles of CaCO3=mass/molar mass=250g/100g/mol=2.5 mol.

The decomposition of CaCO3 is

CaCO3 ------> CaO + CO2

The mole ratio between CaCO3:CO2=1:1.

Therefore moles of CO2 formed=2.5 mol.

At STP, 1 mol of any gas occupies 22.4 L of volume.

Therefore at STP, 2.5 mol of CO2 ovcupies volume=(22.4 L x 2.6 mol)/1 mol=56 L.

Therefore volume of CO2=56 L.

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