Question

The rate constant (k) for a reaction was measured as a function of temperature. A plot...

The rate constant (k) for a reaction was measured as a function of temperature. A plot of lnk versus 1/T(in K) is linear and has a slope of

−1.49×104 K .

Ea=???

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Homework Answers

Answer #1

Answer is 123.8 kj

k = A exp(-Ea / (RT))
and if you take the ln of both sides...
ln(k) = ln(A exp(-Ea / (RT)))
rearranging...
ln(k) = ln(A) + ln(exp(-Ea / (RT)))
ln(k) = ln(A) + -Ea / (RT)
and finally..
ln(k) = (-Ea/R) x (1/T) + ln(A)
and that is of the form..
y = mx + b
IF...
y = ln(k)
m = -Ea/R
x = (1/T)
b = ln(A)


so a plot of ln(k) on the y-axis and (1/T) on the x-axis will have slope = -Ea/R and intercept = ln(A)

where..
Ea = activation energy
R = 8.314 J/moleK

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