Question

A student dissolves 0.326 g of a powdered antacid in 32.36 mL of 0.1034 M HCl....

A student dissolves 0.326 g of a powdered antacid in 32.36 mL of 0.1034 M HCl. The student boils the mixture and then allows it to cool. Lastly, the student adds phenolphthalein indicator to the mixture.

6) Given an antacid costs $5.99 per 100 tablet bottle and the average mass of a tablet is 650 mg, calculate the cost per equivalent (in $/eq) of this antacid.

Homework Answers

Answer #1

Ans :

Number of moles of acid = moalrity x volume (L)

= 0.1034 x 0.03236

= 0.003346 mol

Each mole of acid neutralises one mole of antacid , so the number of equivalents in 0.326 g or 326 mg of powdered antacid is 0.003346 equivalents.

326 mg has 0.003346 eq

so 650 mg antacid tablet will have : ( 650 x 0.003346) / 326 = 0.00667 eq

eq in 100 tablets = 100 x 0.00667 = 0.667 eq

cost of 0.667 eq is $5.99

S0 cost of 1 eq = $ 5.99 / 0.667

= 8.98 $

So the cost per equivalent is 8.98 $/eq of antacid.

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