You need to prepare 200 mL of 1.00 M NaOH from solid NaOH and water. you also need to prepare 200 mL of 6.00 M HCl from concentrated HCl solution.
Describe how you would prepare the NaOH and the HCl solutions. You need to show th data and calculations for the standardization.
use molarity formula
molarity (M) = mass / molar mass x 1000 / volume in mL
mass = mass of NaOH
molar mass = 40 g/mol
volume in mL = 200 mL
Molarity = 1.0 M
1.0 M = mass / 40 g/mol x (1000 / 200)
mass = 1.0 x 8 = 8.0 g
so take 8.0 g of NaOH and then dissolve in some amount water (it should be less than 200) and then make up up to 200 mL
HCl
use same formula
molar mass of HCl = 36.458 g/mol
volume given is 200 mL
Molarity = 6.00 M HCl
plug in these valume
6.0 M = mass / 36.458 g/mol ( 1000 / 200)
Mass = 6.0 M x 5 / 36.458 g/mol
Mass = 0.823 g
dissolve 0.836 g of HCl then add to some amount of water after dissolving every thing make up upto 200 mL
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