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Solid sodium sulfide is slowly added to 55.0 mL of a calcium iodide solution until the...

Solid sodium sulfide is slowly added to 55.0 mL of a calcium iodide solution until the concentration of sulfide ion is 0.0396M. The maximum amount of calcium ion remaining in solution is ______ M.

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Answer #1

Always remember to take all the given quantities in SI unit.

Maximum amount of calcium ion is equal to sulphide ion concentration as in solution we will have one [ca2+] , one [S2-], two [Na+] and two [I-] ion will be present

If u have any doubt u can ask freely.

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