How many mL of cream at 5 degrees with a density of 1.35g/ml must be mixed with 180ml of coffee at 95degrees so that the resulting combinations will have a temperature of 80degres? the specific heat of cream is 3.25j/g C. assume the density of water is 1g/ml
CONCEPT: The problem can be solved by using the following equation
heat gained by ice cream = - Heat lost by coffee
- sign indicates heat is lost
SOLUTION:
Heat lost by coffee = - mass of coffee (Mc) X specific heat of coffee (Cc) X Temperature difference (ΔT)
Mc = Volume X density = 180mL X 1 = 180 g
Cc = specific heat of water = 4.2J/g
ΔT = Tfinal - Tinitial
Similarly heat gained by ice cream = Mi X Ci X ΔT
Ci = specific heat of ice cream
Mi = mass of ice cream = Volume of ice cream (Vi) / density
ΔT = Tfinal - Tinitial
(Vi / density) X Ci X ΔT = Mc X Cc X ΔT
(Vi / 1.35g/mL) X 3.25 J/g/oC X (80 oC- 5oC) = -[180 X 4.2 J/goC X (80oC - 95oC)]
Vi X 180.55 = 11340
Vi = 62.8 mL
Get Answers For Free
Most questions answered within 1 hours.