What is the pH of a solution prepared by dissolving 2.1 g of HCl in water to make 340. mL of solution?
when i did this i ended up getting 2.772, however its incorrect..
I also need help with these :(
complete and balance the equations
concentration of HCl = w/mwt*1000/V
= 0.17 M
pH = -log(H3O+) = -log0.17 = 0.77
ZnCO3(s)+ 2HI(aq) → ZnI2(aq) + CO2(g) + H2O(l)
Zn(s)+ 2HCl(aq) → H2(g) + ZnCl2(aq)
HCl(aq) + NaHCO3(s) → NaCl(aq) + CO2(g) + H2O(l)
Get Answers For Free
Most questions answered within 1 hours.