Question

consider the equilibrium,

I₂(s)+5F₂ (g) <---> 2IF5

for which of the equilibrium constant is 0.750 atm^-3. in a particular experiment, 10.0g of iodine and 1.05 atm of fluorine and 1.05 atm of iodinepentafluoride were introduced into an otherwise empty 5.00 L container at 25 degrees celsius. will the number of grams of iodine increase or decrease when equilibrium is established? justify your answer.

Please show work, thanks!

Answer 1

Ans. Reaction quotient, Q = [IF₅]² / [F₂]⁵

Note that being in solid state, the amount of I₂ is NOT accounted.

            Or, Q = (1.05 atm)² / (1.05 atm)⁵ = 0.864 atm^-3

# Given – Equilibrium constant, Keq = 0.750 atm^-3

# Since Q > Keq, the reaction will proceed to the LEFT/ Backward direction to establish the equilibrium.

Now, because the reaction proceeds in backward direction, there would be formation of more I₂ from IF₅. Thus, the number of grams of iodine will INCREASE.