Consider the combustion reaction of propane gas: C3H8(g) + 5O2(g) → 4H2O(g) + 3CO2(g) Predict the signs (+ positive, - negative, 0 zero, or CBD cannot be determined ), if possible, for the delta Ssystem. Use the symbol to fill the blank.
hi i will try my best to explain you this
first if all, combustion reactions are generally exothermic.. that is energy is released into the sorroundings. so, it has (-) delta H value.
Now if you can see the reaction
C3H8(g) + 5O2(g) → 4H2O(g) + 3CO2(g) all are in gaseous state. in the reactant side,6 molecules and on the product side 7 molecules are present. The increase in gaseous molecules increases the disorder, and therefore the change in entropy (delta S) is (+) .
delta G = -delta H) - T delta S.
delta G = is also negative
hope this is correct and helps you.
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