Question

Suppose a student adds 25.00 mL of 1.041 M HCl to a 1.50 g antacid tablet. The student boils and then titrates the resulting solution to the endpoint with 0.4989 M NaOH. The titration requires 21.1 mL NaOH to reach the endpoint. How many moles of HCl were neutralized by the NaOH?How many moles of HCl were neutralized by the tablet?

Answer 1

volume of HCl = 25.00 mL

concentration = 1.041 M

moles of HCl = 25 x 1.041 / 1000

moles of HCl = 0.02602

volume of NaOH required = 21.1 mL

moles of NaOH = 0.4989 x 0.0211

                          = 0.01053 mol

moles of HCl were neutralized by the NaOH = 0.0105 mol

moles of HCl were neutralized by the tablet = 0.02602 - 0.01053

moles of HCl were neutralized by the tablet = 0.0155 mol