Question

Calculate the f.e.m. for the following reaction at 25oC Au3+(aq) (4.4e-3M) +   2Cl-(aq) (1.3e-2M)      →   Au(s)...

Calculate the f.e.m. for the following reaction at 25oC

Au3+(aq) (4.4e-3M) +   2Cl-(aq) (1.3e-2M)      →   Au(s) ( - M) +   Cl2(g) ( - M)

Ecell = ? (2 decimals accuracy!)

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Homework Answers

Answer #1

balanced equation

2Au3+(aq) (4.4e-3M) + 6Cl-(aq) (1.3e-2M) ---> 2Au(s) ( - M)   +   3Cl2(g) ( - M)


E0Au3+/Au = 1.52 v

E0Cl2/2cl- = 1.36 v


E0cell = E0cathode - E0anode

       = (1.52-1.36)

       = 0.16 V

Ecell = E0cell - 0.0591/nlog(1/[Au3+]^2[Cl-]^6)

       = 0.16 - (0.0591/6)log(1/((4.4*10^(-3))^2(1.3*10^(-2))^6))

       = 0.00211 V

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