Question

you mix excess AgNO3 with 25.0 ml of 0.302 M KCl is the maximun mass in grams of AgCl that can be formed ?g ?

Answer 1

thereaction is

AgNO3 + KCl --> AgCl + KNO3

Here AgNO3 is inexcess so limiting reagent is KCl

USE,

number of mole = molarity*volume of solution (in liter)

number of mole of KCl =(0.302*25)/1000

number of mole of KCl = 7.6*10^-3

acording to above balanced equation 1 mole of KCl produces 1mole of AgCl

so,

7.6*10^-3 mole of KCl produces 7.6*10^-3mole of AgCl

mole of AgCl formed = 7.6*10^-3

mass of AgCl formed/molar mass of AgCl= 7.6*10^-3

molar massof AgCl= 143.3

mass of AgCl formed =  7.6*10^-3*143.3 g

mass of AgCl formed = 1.09 g

answered by: anonymous