Question

# Use standard free energies of formation to calculate ΔG∘ΔG∘ at 25 ∘C∘C for each of the...

Use standard free energies of formation to calculate ΔG∘ΔG∘ at 25 ∘C∘C for each of the following reactions.

 Substance ΔG∘f(kJ/mol)ΔGf∘(kJ/mol) H2O(g)H2O(g) −−228.6 H2O(l)H2O(l) −−237.1 NH3(g)NH3(g) −−16.4 NO(g)NO(g) 87.6 CO(g)CO(g) −−137.2 CO2(g)CO2(g) −−394.4 CH4(g)CH4(g) −−50.5 C2H2(g)C2H2(g) 209.9 C2H6(g)C2H6(g) −−32.0 Fe3O4(s)Fe3O4(s) −−1015.4 KClO3(s)KClO3(s) −−296.3 KCl(s)KCl(s) −−408.5

Part A

C(s,graphite)+2H2(g)→CH4(g)C(s,graphite)+2H2(g)→CH4(g)

Express your answer to one decimal place and include the appropriate units.

Part B

Fe3O4(s)+4H2(g)→3Fe(s)+4H2O(g)Fe3O4(s)+4H2(g)→3Fe(s)+4H2O(g)

Express your answer to one decimal place and include the appropriate units.

Part C

N2(g)+O2(g)→2NO(g)N2(g)+O2(g)→2NO(g)

Express your answer to one decimal place and include the appropriate units.

Part D

2KClO3(s)→2KCl(s)+3O2(g)2KClO3(s)→2KCl(s)+3O2(g)

Express your answer to one decimal place and include the appropriate units.

C(s,graphite)+2H2(g)→CH4(g)

ΔG = [1ΔGf(CH4 (g))] - [1ΔGf(C (s graphite)) + 2ΔGf(H2 (g))]
ΔG = [1(-50.5)] - [1(0) + 2(0)] = -50.5 kJ

Fe3O4(s)+4H2(g)→3Fe(s)+4H2O(g)

ΔG = [3ΔGf(Fe (s)) + 4ΔGf(H2O (g)) ] - [1ΔGf(Fe3O4(s)) + 4ΔGf(H2 (g))]

ΔG = [3(0) + 4(228.6)] - [1(1015.4) + 2(0)] = -101 kJ

N2(g)+O2(g)→2NO(g)

ΔG = [2ΔGf(NO (g)] - [1ΔGf(N2 (g)) + ΔGf(O2 (g))]

ΔG = [2(87.6)] - [1(0) + 2(0)] = 175.2 kJ

2KClO3(s)→2KCl(s)+3O2(g)

[2ΔGf(KCl (s)) + 3ΔGf(O2 (g))] - [2ΔGf(KClO3 (s))]

[2(-408.5) + 3(0)] - [2(-296.3)] = -224.4 kJ

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