Use standard free energies of formation to calculate ΔG∘ΔG∘ at 25 ∘C∘C for each of the following reactions.
Substance | ΔG∘f(kJ/mol)ΔGf∘(kJ/mol) |
H2O(g)H2O(g) | −−228.6 |
H2O(l)H2O(l) | −−237.1 |
NH3(g)NH3(g) | −−16.4 |
NO(g)NO(g) | 87.6 |
CO(g)CO(g) | −−137.2 |
CO2(g)CO2(g) | −−394.4 |
CH4(g)CH4(g) | −−50.5 |
C2H2(g)C2H2(g) | 209.9 |
C2H6(g)C2H6(g) | −−32.0 |
Fe3O4(s)Fe3O4(s) | −−1015.4 |
KClO3(s)KClO3(s) | −−296.3 |
KCl(s)KCl(s) | −−408.5 |
Part A
C(s,graphite)+2H2(g)→CH4(g)C(s,graphite)+2H2(g)→CH4(g)
Express your answer to one decimal place and include the appropriate units.
Part B
Fe3O4(s)+4H2(g)→3Fe(s)+4H2O(g)Fe3O4(s)+4H2(g)→3Fe(s)+4H2O(g)
Express your answer to one decimal place and include the appropriate units.
Part C
N2(g)+O2(g)→2NO(g)N2(g)+O2(g)→2NO(g)
Express your answer to one decimal place and include the appropriate units.
Part D
2KClO3(s)→2KCl(s)+3O2(g)2KClO3(s)→2KCl(s)+3O2(g)
Express your answer to one decimal place and include the appropriate units.
C(s,graphite)+2H2(g)→CH4(g)
ΔG = [1ΔGf(CH4 (g))] - [1ΔGf(C (s
graphite)) + 2ΔGf(H2 (g))]
ΔG = [1(-50.5)] - [1(0) + 2(0)] = -50.5 kJ
Fe3O4(s)+4H2(g)→3Fe(s)+4H2O(g)
ΔG = [3ΔGf(Fe (s)) + 4ΔGf(H2O (g)) ] - [1ΔGf(Fe3O4(s)) + 4ΔGf(H2 (g))]
ΔG = [3(0) + 4(228.6)] - [1(1015.4) + 2(0)] = -101 kJ
N2(g)+O2(g)→2NO(g)
ΔG = [2ΔGf(NO (g)] - [1ΔGf(N2 (g)) + ΔGf(O2 (g))]
ΔG = [2(87.6)] - [1(0) + 2(0)] = 175.2 kJ
2KClO3(s)→2KCl(s)+3O2(g)
[2ΔGf(KCl (s)) + 3ΔGf(O2 (g))] - [2ΔGf(KClO3 (s))]
[2(-408.5) + 3(0)] - [2(-296.3)] = -224.4 kJ
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