Question

A **He** atom with a mass of 6.65×10−27 kg has a de
Broglie wavelength of 4.3×10−12 m. What is the velocity of the
**He** atom, in meters per second?

Use 6.626×10−34kg m2s for Planck's constant.

Your answer should include two significant figures.

Answer #1

**Solution
:**

The expression for de Broglie wavelength is given by :

where
= de Broglie wavelength = 4.3
10^{-12} m ; h = Plank's constant = 6.626
10^{-34} kgm^{2}s ; p = momentum = mv ; m = mass
of He atom = 6.65
10^{-27} kg ; v = Velocity of He atom = To be
calculated;

Therefore, **velocity of He atom = 2.3
10 ^{4} m/s**

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