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A He atom with a mass of 6.65×10−27 kg has a de Broglie wavelength of 4.3×10−12...

A He atom with a mass of 6.65×10−27 kg has a de Broglie wavelength of 4.3×10−12 m. What is the velocity of the He atom, in meters per second?

Use 6.626×10−34kg m2s for Planck's constant.

Your answer should include two significant figures.

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Homework Answers

Answer #1

Solution :

The expression for de Broglie wavelength is given by :

where = de Broglie wavelength = 4.3 10-12 m ; h = Plank's constant = 6.626 10-34 kgm2s ; p = momentum = mv ; m = mass of He atom = 6.65 10-27 kg ; v = Velocity of He atom = To be calculated;

Therefore, velocity of He atom = 2.3 104 m/s

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