Question

(e) What do you expect to see if you mix octane with KMnO4? (f) What do...

(e) What do you expect to see if you mix octane with KMnO4?

(f) What do you expect to see if you mix 2-hexene with KMnO4?

(d) What do you expect to see if you mix octane with concentrated H2SO4?

(e) What do you expect to see if you mix 2-hexene with concentrated H2SO4?

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Answer #1

As we know that KMnO4 and H2SO4 will react with an alkene and they do not react with alkanes.

(e)There is no reaction of octane with KMnO4 because octane is an alkane. So, there is no change in the purple solution of KMnO4 solution. Note: the name of this test is Baeyer's test.

(f) 2-hexene is an alkene that reacts with KMnO4 and gives a positive Baeyer's test where purple color of KMnO4 changes to brown as MnO2 is formed.

(d) As octane is an alkane which does not show reaction with H2SO4. So, an insoluble solution of an alkane is observed in the mixture.

(e) 2-hexene reacts with H2SO4 to form 2-hexyl hydrogen sulfate product which is soluble in concentration H2SO4. So, we observed a clean solution after mixing 2-hexene with H2SO4.

Let me know if you have any queries regarding this.   

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