Question

calculate the volume of 1.50 × 10-2 M NaOH that must be added to 500.0 mL...

calculate the volume of 1.50 × 10-2 M NaOH that must be added to 500.0 mL of 0.200 M HCl to give a solution that has pH = 2.05

.Volume = __L

Homework Answers

Answer #1

      PH = 2.05

   -log[H^+] = 2.05

       [H^+]   = 10^-2.05   = 0.0089M    it is resultant molarity

    HCl                     NaOH

MA = 0.2M    MB = 1.5*10^-2M = 0.015M

VA = 500ml VB =

M    = MAVA- MBVB/VA+VB

0.0089 = 0.2*500-0.015*VB/500+VB

0.0089*(500+VB) = 0.2*500-0.015*VB

VB = 3997.9ml

The volume of NaOH = 3998ml = 3.998L >>>>answer

                         

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