Question

Consider an ionic compound, MX2, composed of generic metal M and generic, gaseous halogen X. The...

Consider an ionic compound, MX2, composed of generic metal M and generic, gaseous halogen X.

The enthalpy of formation of MX2 is ΔHf° = –979 kJ/mol. The enthalpy of sublimation of M is ΔHsub = 127 kJ/mol. The first and second ionization energies of M are IE1 = 739 kJ/mol and IE2 = 1396 kJ/mol. The electron affinity of X is ΔHEA = –325 kJ/mol. (Refer to the Hint). The bond energy of X2 is BE = 169 kJ/mol.

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Consider an ionic compound, MX2MX2, composed of generic metal MM and generic, gaseous halogen XX. -The...
Consider an ionic compound, MX2MX2, composed of generic metal MM and generic, gaseous halogen XX. -The enthalpy of formation of MX2MX2 is Δ?∘f=−691ΔHf∘=−691 kJ/mol. -The enthalpy of sublimation of MM is Δ?sub=127ΔHsub=127 kJ/mol. -The first and second ionization energies of MM are IE1=671IE1=671 kJ/mol and IE2=1448IE2=1448 kJ/mol. -The electron affinity of XX is Δ?EA=−311ΔHEA=−311 kJ/mol. (Refer to the hint). -The bond energy of X2X2 is BE=167BE=167 kJ/mol. Determine the lattice energy of MX2MX2.
Calculate the second ionization energy of the metal M (ΔHion2° in kJ/mol) using the following data:...
Calculate the second ionization energy of the metal M (ΔHion2° in kJ/mol) using the following data: Lattice enthalpy of MO(s), ΔHl° = -2297 kJ/mol Bond dissociation enthalpy of O2(g) = +498 kJ/mol First electron affinity of O = -141 kJ/mol Second electron affinity of O = +744 kJ/mol Enthalpy of sublimation of M = + 102 kJ/mol First ionization energy of M = + 340 kJ/mol Standard enthalpy of formation of MO(s), ΔHf° = -336 kJ/mol Refer to the textbook...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT