Nickel forms a gaseous compound Ni(CO)x. Under the same temperature and pressure, CH4 effuses through a small opening in 11.5 minutes, while Ni(CO)x effuses in 37.9 minutes. What is the value of x?
RATE OF EFFUSION = SQUARE ROOT OF M1/M2= R1/R2
WHERE M1= MASS OF NI(CO)x= 58.7 +x*28.7
M2= MASS OF CH4=16
R1= RATE OF EFFUSION OF NI(CO)x=37.9 minutes
R2 = RATE OF EFFUSION OF CH4 = 11.5 minutes
PUT THE VALUE IN THE FORMULA, AFTER SQUARING BOTH SIDES THE FORMULA BECOMES M1/M2=(R1*R1)/(R2*R2)
(58.7+x*28)/16 = 37.9*37.9/11.5*11.5
58.7 + x*28 = 10.8613 * 16
58.7 + x*28 = 173.7808
x*28 = 173.7808-58.7
x*28=115.0808
x= 115.0808/28
x=4.11
it is nearly equal to
so our formula is NI(CO)4
IF YOU ARE SATISFY WITH THE ANSWER PLEASE LIKE IT .
Get Answers For Free
Most questions answered within 1 hours.