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Determine the correct hybridizaton (from left to right) about each interior atom in CH≡CCH2Cl. Determine the...

Determine the correct hybridizaton (from left to right) about each interior atom in CH≡CCH2Cl.

Determine the correct hybridizaton (from left to right) about each interior atom in .

a. 1st Csp2; 2nd Csp2; 3rd Csp3
b. 1st Csp; 2nd Csp3; 3rd Csp2
c. 1st Csp; 2nd Csp2; 3rd Csp2
d. 1st Csp; 2nd Csp; 3rd Csp3
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Answer #1

the hybridisation follows below rule:

When there are 2 electron domain —> sp

When there are 3 electron domain —> sp2

When there are 4 electron domain —> sp3

When there are 5 electron domain —> sp3d

1st C:

forms 2 sigma bond.

forms 2 pi bonds.

Since pi bonds are not considered in hybridisation, it is sp hybridised.

2nd C:

forms 2 sigma bond.

forms 2 pi bonds.

Since pi bonds are not considered in hybridisation, it is sp hybridised.

3rd C:

forms 4 sigma bond.

So, it is sp3 hybridised

Answer: d

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