Question

If you had started with 2.60 grams of Na2CO3 and reacted it with excess of HCl,...

If you had started with 2.60 grams of Na2CO3 and reacted it with excess of HCl, what mass of NaCl in grams would you expect to produce?

Homework Answers

Answer #1

Molar mass of Na2CO3,

MM = 2*MM(Na) + 1*MM(C) + 3*MM(O)

= 2*22.99 + 1*12.01 + 3*16.0

= 105.99 g/mol

mass(Na2CO3)= 2.6 g

use:

number of mol of Na2CO3,

n = mass of Na2CO3/molar mass of Na2CO3

=(2.6 g)/(1.06*10^2 g/mol)

= 2.453*10^-2 mol

Balanced chemical equation is:

Na2CO3 + 2 HCl ---> 2 NaCl + H2O + CO2

Molar mass of NaCl,

MM = 1*MM(Na) + 1*MM(Cl)

= 1*22.99 + 1*35.45

= 58.44 g/mol

According to balanced equation

mol of NaCl formed = (2/1)* moles of Na2CO3

= (2/1)*0.0245

= 0.0491 mol

use:

mass of NaCl = number of mol * molar mass

= 4.906*10^-2*58.44

= 2.867 g

Answer: 2.87 g

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