Question

A chemical reaction produces 0.127mol of CO2 gas at 23degrees centigrate and 727mm Hg. What is volume in liters should this sample occupy?

Answer 1

Given,

Temperature of the gas = 23 0C = 23+273.15 = 296.15K

Pressure of the gas = P = 727 mm of Hg

= 727 × (1 / 760) = 0.956 atm

No.of moles of gas = n = 0.127 mol

Assume, given gas is an Ideal gas.

So, From ideal gas law,

PV = nRT

Where, P = pressure of the gas ( atm )

T = Temperature of the gas ( K )

n = no.of moles of gas ( mol )

R = ideal gas constant ( L . atm / mol.K )

= 0.0821 L.atm / K.mol

V = Volume of the gas ( L )

Therefore , PV = nRT

==> V = nRT / P = ( 0.127×0.0821×296.15 ) / 0.956

= 3.23 L

Therefore, Volume occupied by the gas = 3.23 L