Question

The Kb for A- is 4.9x10^-10. What is the pOH of a 0.0727 M aqueous solution at 25 degrees C.

Answer #1

Lets write the dissociation equation of A-

A- +H2O -----> HA + OH-

7.27*10^-2 0 0

7.27*10^-2-x x x

Kb = [HA][OH-]/[A-]

Kb = x*x/(c-x)

Assuming small x approximation, that is lets assume that x can be ignored as compared to c

So, above expression becomes

Kb = x*x/(c)

so, x = sqrt (Kb*c)

x = sqrt ((4.9*10^-10)*7.27*10^-2) = 5.969*10^-6

since c is much greater than x, our assumption is correct

so, x = 5.969*10^-6 M

So, [OH-] = x = 5.969*10^-6 M

we have below equation to be used:

pOH = -log [OH-]

= -log (5.969*10^-6)

= 5.22

Answer: 5.22

1)
Kb for NH3 is 1.8x10^-5. What is the pOH of a .20M aqueous solution
of NH4Cl at 25 degrees Celsius? (Please show work)
2) Determine the pH of a 0.15 M aqueous solution of KF. For
hydrofluoric acid, Ka=7.0x10^-4. (Please show work)
3) An aqueous solution of _____ will produce a neutral
solution.
A) NaNO2
B) LiNO3
C) KF
D) Rb2CO3
E) NH4NO3

Part A: If Kb for NX3 is 9.5×10−6, what is the pOH of a 0.175 M
aqueous solution of NX3?
Part B: If Kb for NX3 is 9.5×10−6, what is
the percent ionization of a 0.325 M aqueous
solution of NX3?
Part C: If Kb for NX3 is 9.5×10−6 , what is
the the pKa for the following reaction?
HNX3+(aq)+H2O(l)⇌NX3(aq)+H3O+(aq)

Part A If Kb for NX3 is 6.0×10−6, what is
the pOH of a 0.175 M aqueous solution of NX3
Part B
If Kb for NX3 is 6.0×10−6, what is the
percent ionization of a 0.325 M aqueous solution of
NX3?
Part C
If Kb for NX3 is 6.0×10−6 , what is the the
pKa for the following reaction?
HNX3+(aq)+H2O(l)⇌NX3(aq)+H3O+(aq)

Part A: If Kb for NX3 is 9.0×10−6, what is the pOH of a 0.175 M
aqueous solution of NX3? Express your answer numerically.
Part B: If Kb for NX3 is 9.0×10−6, what is
the percent ionization of a 0.325 M aqueous solution of
NX3?
Part C: If Kb for NX3 is 9.0×10−6 , what is
the the pKa for the following reaction?
HNX3+(aq)+H2O(l)⇌NX3(aq)+H3O+(aq)

Part A If Kb for NX3 is
7.0×10−6, what is the pOH of a 0.175 M aqueous
solution of NX3? Express your answer numerically.
Part B If Kb for NX3 is
7.0×10−6, what is the percent ionization of
a 0.325 M aqueous solution of NX3?
Express your answer numerically to three significant figures.
Part C If Kb for NX3 is
7.0×10−6 , what is the the pKa for the
following reaction?
HNX3+(aq)+H2O(l)⇌NX3(aq)+H3O+(aq)
Express your answer numerically to two decimal places.

Part A
If Kb for NX3 is 6.0×10−6, what is the pOH
of a 0.175 M aqueous solution of NX3?
Express your answer numerically.
Part B
If Kb for NX3 is 6.0×10−6, what is the
percent ionization of a 0.325 M aqueous solution of
NX3?
Express your answer numerically to three significant
figures.
Part C
If Kb for NX3 is 6.0×10−6 , what is the the
pKa for the following reaction?
HNX3+(aq)+H2O(l)⇌NX3(aq)+H3O+(aq)
Express your answer numerically to two decimal places.

A .calculate the ph and poh of an aqueous solution that is
0.050M in HCL (aq) and 0.075M in HBr(aq) at 25 degrees C
ph=
poh=
B . assuming complete dissociation what is the ph of a 3.93 mg/L
Ba(OH)2 solution?
ph=

Part A
What is the H+ concentration for an aqueous solution with pOH =
3.26 at 25 ∘C?
Express your answer to two significant figures and include the
appropriate units.
Arrange the following aqueous solutions, all at 25 ∘C, in order
of decreasing acidity.
Rank from most acidic to most basic. To rank items as
equivalent, overlap them.
pOH = 8.55
pH = 5.45
0.0023 M HCl
0.0018 M KOH
Part C
At a certain temperature, the pH of a...

1a. The pOH of an aqueous
solution at 25°C was found to be 5.10.
The pH of this solution is ____.
The hydronium ion concentration is ____M.
The hydroxide ion concentration is ____M.
1b. The pH of an aqueous
solution at 25°C was found to be 10.00.
The pOH of this solution is ______.
The hydronium ion concentration is ____ M.
The hydroxide ion concentration is ____M.

Kb for NH3 is 1.8 X 10^-5. What is the pOH of a 0.50 M aquesous
solution of NH4CL at 25 degree C?
a) 9.22
b) 11.23
c) 11.48
d) 4.78
e) 2.52
Please show work, I have gotten mulitple answers different answers
so I'm confused on which steps I am doing or not doing.
Thanks!!!

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