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Calculate the solubility of Mercury (I) carbonate, Hg2CO3 if its solubility product constant, Ksp is 8.9...

Calculate the solubility of Mercury (I) carbonate, Hg2CO3 if its solubility product constant, Ksp is 8.9 X 10^-17

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Answer #1

Ksp = 8.9x10^-17

Hg2CO3 ---------------------- 2 Hg+ + CO3-2

                                             2S               S                where S=molar solubility

Ksp = [Hg+]^2[CO3-2]

Ksp = (2s)^2 (S)

Ksp = 4S^3

S^3=Ksp/4

S^3 = 8.9x10^-17/4=2.225 x10^-17=22.25x10^-18

S=2.812x10^-6

Solubity of Hg2CO3= 2.81x10^-6 M

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