Based on knowledge of the electronic configuration of niobium, state which of the following compounds of niobium is unlikely to exist.
Ca2NbO4 |
NaNbO3 |
Na2NbO2 |
Ca3NbO6 |
Na3NbO3 |
oxidation state of Nb in Ca2NbO4 = +4
oxidation state of Nb in NaNbO3 = +5
oxidation state of Nb in Na2NbO2 = +2
oxidation state of Nb in Ca3NbO6 = +6
oxidation state of Nb in Na3NbO3 = +3
Number of electron in Nb = 41
Electronic configuration is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d4 5s1
Explanation: d block anomaly
Noble gas having lesser electron than Nb and closest to it is Krypton (Kr)
Number of electron in Kr = 36
electronic configuration of Kr is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6
So, electronic configuration of Nb in noble gas form is: [Kr] 4d4 5s1
It can loose maximum 5 electrons and hence can form upto +5 oxidation state
Oxidation state of +6 is not possible for Nb
Answer: Ca3NbO6
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