Question

ARRHENIUS EQUATION CALCULATIONS The activation energy for the gas phase decomposition of dinitrogen pentoxide is 103 kJ. N2O52 NO2 + 1/2 O2 The rate constant at 319 K is 5.59×10-4 /s. The rate constant will be 6.37×10-3 /s at ______ K.

PART 2 The activation energy for the gas phase isomerization of isopropenyl allyl ether is 123 kJ. CH2=C(CH3)-O-CH2CH=CH2CH3COCH2CH2CH=CH2 The rate constant at 432 K is 2.68×10-4 /s. The rate constant will be______ /s at 474 K.

Answer #1

1)

Given:

T1 = 319 K

K1 = 5.59*10^-4 /s

K2 = 6.37*10^-3 /s

Ea = 103 KJ/mol

= 103000 J/mol

use:

ln(K2/K1) = (Ea/R)*(1/T1 - 1/T2)

ln(6.37*10^-3/5.59*10^-4) = (103000.0/8.314)*(1/319 - 1/T2)

2.4332 = 12388.7419*(1/319 - 1/T2)

T2 = 340 K

Answer: 340 K

2)

Given:

T1 = 432 K

T2 = 474 K

K1 = 2.68*10^-4 /s

Ea = 123 KJ/mol

= 123000 J/mol

use:

ln(K2/K1) = (Ea/R)*(1/T1 - 1/T2)

ln(K2/2.68*10^-4) = (123000.0/8.314)*(1/432 - 1/474.0)

ln(K2/2.68*10^-4) = 14794*(2.051*10^-4)

K2 = 5.572*10^-3 /s

Answer: 5.57*10^-3 /s

The activation energy for the gas phase isomerization of vinyl
allyl ether is 128 kJ.
CH2CH-O-CH2CH=CH2----------->CH2CHCH2CH2CHO
The rate constant at 450 K is 2.81×10-4 /s.
The rate constant will be 2.24×10-3 /s at ____________ K.

1) The gas phase decomposition of dinitrogen pentoxide at 335
K
N2O5(g) 2
NO2(g) + ½ O2(g)
is first order in
N2O5 with a rate constant of
4.70×10-3
s-1.
If the initial concentration of
N2O5 is
0.105 M, the concentration of
N2O5 will
be Mafter 391 s have
passed.
2) The gas phase decomposition of dinitrogen pentoxide at 335
K
N2O5(g)2
NO2(g) + ½ O2(g)
is first order in
N2O5 with a rate constant of
4.70×10-3
s-1.
If the initial concentration of...

For the gas phase decomposition of vinyl ethyl ether,
CH2=CH-OC2H5C2H4 + CH3CHO the rate constant has been determined at
several temperatures. When ln k in s-1 is plotted against the
reciprocal of the Kelvin temperature, the resulting linear plot has
a slope of -2.20×104 K and a y-intercept of 26.3. The activation
energy for the gas phase decomposition of vinyl ethyl ether is
kJ/mol.

In a series of experiments on the decomposition of dinitrogen
pentoxide, N2O5, rate constants were
determined at two different temperatures. At 35°C, the rate
constant was 1.4×10-4/s; at 45°C, the rate constant was
5.0×10-4/s.
(a) What is the activation
energy for this reaction?
(b) What is the value of the
rate constant at 85°C?

The gas phase reaction
2N2O5(g)->4NO2(g)+O2(g)
has an activation energy of 103 kJ/mole, and the first order
rate constant is 1.16x10^-8 min^-1 at 231 K. what is the rate
constant at 211K?

A certain gas-phase reaction is first order in each of the
reactants. The energy of activation for the reaction is 39.7 kJ
mol−1. At 65 °C the rate constant is 0.35 m3 mol−1 s−1. Calculate
the entropy of activation at 65 °C.
The answer should be 44.1 kJ/mol

± The Arrhenius Equation
The Arrhenius equation shows the relationship between the rate
constant k and the temperature T in kelvins and
is typically written as
k=Ae−Ea/RT
where R is the gas constant (8.314 J/mol⋅K), A
is a constant called the frequency factor, and Ea
is the activation energy for the reaction.
However, a more practical form of this equation is
lnk2k1=EaR(1T1−1T2)
which is mathmatically equivalent to
lnk1k2=EaR(1T2−1T1)
where k1 and k2 are the rate constants for a
single reaction...

For the decomposition of gaseous dinitrogen pentoxide
(shownbelow), the rate constant is k = 2.8 10-3 s-1 at 60°C. The
initialconcentration of N2O5 is 2.31 mol/L. 2 N2O5(g) 4NO2(g) +
O2(g) (a) What is [N2O5] after 5.00 min? _____mol/L (b) What
fraction of the N2O5 has decomposed after 5.00 min?

if the decomposition of N2O5 has an activation energy
of 103 kJ/mole and a frequency factor of 4.3 *10^13 s^-1. what is
the rate constant for this decomposition at 20°C?100°C?

± The Arrhenius Equation
The Arrhenius equation shows the relationship between the rate
constant k and the temperature T in kelvins and
is typically written as
k=Ae−Ea/RT
where R is the gas constant (8.314 J/mol⋅K), A is
a constant called the frequency factor, and Eais
the activation energy for the reaction.
However, a more practical form of this equation is
lnk2k1=EaR(1T1−1T2)
which is mathmatically equivalent to
lnk1k2=EaR(1T2−1T1)
where k1 and k2 are the rate constants for a
single reaction at...

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