Question

USE MY TABLE TO ANSWER ALL QUESTIONS

Trial	Barometric Pressure (atm)	Temperature (°C)	Mass of Chemical (g)	Water Displaced (mL)
Trial 1 NaHCO3	1.006973	20C	1.0g	.057L
Trial 2 NaHCO3	1.006973	20C	1.0g	.085L
Trial 3 Na2CO3	1.006973	21C	1.0g	.042L
Trial 4 Na2CO3	1.006973	20C	1.1g	.036L

PART A Show your calculation for the molar volume of CO2 from Trial 1 according to your experimental data. Show all work, values, and units in your calculations in order to receive full credit. Your work must be complete, logical, and presented in the correct sequence of operations

PART B Show your calculation for the molar volume of CO2 from Trial 2 according to your experimental data. Show all work, values, and units in your calculations in order to receive full credit. Your work must be complete, logical, and presented in the correct sequence of operations

PART C Show your calculation for the molar volume of CO2 from Trial 3 according to your experimental data. Show all work, values, and units in your calculations in order to receive full credit. Your work must be complete, logical, and presented in the correct sequence of operations.

PART D Show your calculation for the molar volume of CO2 from Trial 4 according to your experimental data. Show all work, values, and units in your calculations in order to receive full credit. Your work must be complete, logical, and presented in the correct sequence of operations.

PART E What is the average experimental molar volume of the gas of all 4 trials? Show all work, values, and units in your calculations in order to receive full credit. Your work must be complete, logical, and presented in the correct sequence of operations.

PART F What is the percent error in your calculation? Show all work, values, and units in your calculations in order to receive full credit. Your work must be complete, logical, and presented in the correct sequence of operations

Answer 1

Trial	Barometric Pressure (atm)	Temperature (°C)	Temperature (K)	Mass of Chemical (g)	Water Displaced (mL)
Trial 1 NaHCO3	1.006973	20	20 + 273 = 293	1.0	57
Trial 2 NaHCO3	1.006973	20	293	1.0	85
Trial 3 Na2CO3	1.006973	21	21 + 273 = 294	1.0	42
Trial 4 Na2CO3	1.006973	20	293	1.1	36

A. The no. of moles of NaHCO3 = 1 g / 84 g mol^-1 = 0.012 mol

NaHCO3 + H2O NaOH + H2O + CO2

1 mole of NaHCO3 produces 1 mole of CO2

According to the ideal gas equation, PV = nRT

i.e. V = nRT/P

= 0.012 mol * 0.0821 L atm mol^-1 K^-1 * 293 K / 1.006973 atm

= 0.284 L

Therefore, the molar volume of CO2 = 0.284 L / 0.012 mol = 23.7 L/mol

Similarly, you can determine the molar volume in the remaining trails.

All the best!!!