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calculate delta e for the n= 4 to the n=2 transition of an electron in a...

calculate delta e for the n= 4 to the n=2 transition of an electron in a hydrogen atom. Where on the electromagnetic spectrum would this appear? what does the sign of this value mean?
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Answer #1

En     = -2.172*10^-18/n^2

       n= 2

E2     =   -2.172*10^-18/(2)^2

         = -5.43*10^-19 J

En     = -2.172*10^-18/n^2

       n= 4

E4     =   -2.172*10^-18/(4)^2

          = -1.3575*10^-19J

E   = E4-E2   = -1.3575*10^-19-(-5.43*10^-19)

                          = 4.0725*10^-19 J

when electron transfer from n= 4 to n=2 balmer series formed in visible region.

Balmer series and visible region.

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