a. Calulate the R40 conentration of your unknown sample?
b. Calculate the B1 concentration of your unknown sample?
using the following data
Fraction 1 (Unknwon R 40) @ 505 nm Absorbance is 0.14179
Fraction 2 (Unknown B1) @ 630 nm absorbance is 0.41433
R40 Standard (5ppm) @ 505 nm absorbance is 0.26298
B1 Standard (5ppm) @ 630 nm absorbance is 0.85971
As the absorbance are measured under same wavelength for same compounds we can use Beer's law which states that Absorbance = eLc where c is the concentration and e is the molar extinction coefficient and L is the path length
and we know that we have same wavelength and path length hence
we can use C1 = (A1 / A2) * C2
Where C1 is the unknown concentration and C2 is the known standard concentration
For R40
C2=5ppm
A2=0.26298
A1=0.14179
HENCE C1=5*(0.14179/0.26298)=2.695 PPM
FOR B1
C2=5ppm
A2=0.85971
A1=0.41433
HENCE C1=5*(0.41433/0.85971)=2.41 PPM
Please do give a thumbs up as it matters a lot and leave a comment in case there are doubts.
Get Answers For Free
Most questions answered within 1 hours.