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How much does the enzyme staphylococcal nuclease (Rate enhancement = 5.6 X1014) decrease the activation free...

How much does the enzyme staphylococcal nuclease (Rate enhancement = 5.6 X1014) decrease the activation free energy of its reaction at 25°C?

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Answer #1

The formula to find out the activation free energy is
                          Go = -RTln k
     Go - The activation free energy
          R - 8.3145 J/mol-K (Gas constant)
          T - temperature (298 K )
          k - rate enhancement; 5.6 x 1014

Let's apply the values given and calculate,


     Go = - (8.3145 J/mol-K)(298 K)/(1000 J/kJ) ln (5.6 x 1014 )
    

     Go = - 84.2 kJ/mol

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