Question

(Part A) A sample of helium occupies 1820 mL at 719 mmHg. Part A Assume that the temperature is held constant and determine the volume of the helium at 765 mm Hg? Express your answer with the appropriate units.

(Part B) Assume that the temperature is held constant and determine the pressure, in mmHg, if the volume is changed to 390 mL . Express your answer with the appropriate units.

Answer 1

Part -A

According to Boyles law "For a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional."

Mathematical form is P₁ X V₁ = P₂ X V₂ ----- Equation 1 (AT CONSTANT TEMPERATURE)

Now in our problem P₁ = 719 mmHG , V₁ = 1820 mL , P₂ = 765 mmHG and V₂ = ?

Putting all these in equation 1

719 x 1820 = 765 x V₂

_=> V₂ =( 719 X 1820 ) / 765 = 1710.5 mL

Part -B

Here P₁ = 719 mmHG ,  V₁ = 1820 mL , P₂ = ? and V₂ = 390 mL

Putting all these in equation 1

719 x 1820 = P₂ x 390

=> P₂ = ( 719 x 1820 ) / 390 = 3355.33 mmHg

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