Question

How many millilitres (ml) of 0.75 M NaOH (sodium hydroxide) is needed to completely react with 50 ml of 0.3 M H₂SO₄ (sulfuric acid)?

H₂SO₄ + 2NaOH -> Na₂SO₄ + 2H₂O

How much gram sodium salt (Na₂SO₄) is produced?

Answer 1

molarity of H2SO4 = number of moles of H2SO4 / volume of solution in L

0.3 = number of moles of H2SO4 / 0.05 L

number of moles of H2SO4 = 0.015 mole

from the balanced equation we can say that

1 mole of H2SO4 requires 2 mole of NaOH so

0.015 mole of H2SO4 will require 0.03 mole of NaOH

Molarity of NaOH = number of moles of NaOH / volume of solution in L

0.75 = 0.03 mole / volume of solution in L

volume of solution in L = 0.03 / 0.75 = 0.04 L

1L = 1000 mL

0.04 L = 40 mL

Therefore, the volume of NaOH needed is 40 mL

from the balanced equation we can say that

1 mole of H2SO4 produces 1 mole of Na2SO4 so

0.015 mole of H2SO4 will produce 0.015 mole of Na2SO4

1 mole of Na2SO4 = 142.04 g

0.015 mole of Na2SO4 = 2.13 g

Therefore, the mass of Na2SO4 produced will be 2.13 g