solubilty of X in 100 ml solvent 0 C (water 2.7g) (ethanol 1.4g)
Solubility of X in 100 ml solvent at boiling point of solvent (water 15.7g) (ethanol 24.0g)
1.ml of boiling solvent required to disolve 25g of X
2.g of X that will remain soluable in this amount of solvent when cooled to 0C
3. g of X that will crstallize from the volume of solvent used in (a) when cooled to 0 C
4. % recovery of X for each solvent
Density of water is consider = 1g/cc and density of ethanol = 0.789g/cc
1. amount of boiling water required to dissolve 25g X = (100 x 25)/15.7 = 159.24 ml
amount of boiling ethanol required to dissolve 25g X = (100 x 25)/24 = 104.17 ml
2. amount of X that will be remain soluable in water when cooled to 0C = (2.7 x 159.24)/100 = 4.30g
amount of X that will be remain soluable in ethanol when cooled to 0C = (1.4 x 104.17)/100 = 1.46g
3. amount that can be crystallized in water = 25 - 4.30 = 20.70g
amount that can be crystallized in ethanol = 25 - 1.46 = 23.54g
4. % recovery of X in water = (20.7/25.0) x 100 = 82.8
% recovery of X in ethanol = (23.54/25.0) x 100 = 94.16
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