Question

The first-order decomposition of N2O at a fixed temperature has a rate constant of 0.385 s-1. If the initial concentration of N2O is 21.4 M, what is the concentration of N2O after 50 s?

Answer #1

[A0] = 21.4M

t = 50s

K = 0.385s^-1

K = 2.303/t log[A0]/[A]

0.385 = 2.303/50 log21.4/[A]

log21.4/[A] = 0.385*50/2.303

log21.4/[A] = 8.3586

21.4/[A] = 10^8.3586

21.4/[A] = 228349465.8

[A] = 21.4/228349465.8 = 9.37*10^-8 M

The concentration of N2O after 9.37*10^-8 M

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