Confusion about the question.................
How the process is being carried out ?? This is the case of free expansion of ideal gas....
PV = RT
V = RT/P = (1 mol) (8.314 x 10-2 L bar K-1 mol-1 x 26.85 K)/3.25 bar = 0.69 L (round off)
Pf = RT/Vf = (1 mol) (8.314 x 10-2 L bar K-1 mol-1 x 26.85 K)/1.75 L = 1.28 bar
This is a case of free expansion of ideal gas against zero pressure. This is usually carried out at constant temperature (isothermally). = 0, Tf=Ti
So, w = 0, Q= = 0,
= + = = 0 [ since no change in external pressure, no work involved]
Vf Pf Tf w Q
1.75L 1.28 bar 26.85K 0 0 0 0
For an ideal gas U and H are function of temperature only
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