Question

Calculate the energy of a photon of electromagnetic radiation at each of the following frequencies

Express your answer in joules using four significant figures.

102.7 MHz (typical frequency for FM radio broadcasting)

1050. kHz (typical frequency for AM radio broadcasting)

836.4 MHz (common frequency used for cell phone communication)

Answer 1

1)

frequency = 102.7 MHz = 1.027*10^8 Hz

we have below equation to be used

E = h*f

=(6.626*10^-34 J.s)*(1.027*10^8) s-1

= 6.805*10^-26 J

Answer: 6.805*10^-26 J

2)

frequency = 1050 kHz = 1.050*10^6 Hz

we have below equation to be used

E = h*f

=(6.626*10^-34 J.s)*(1.050*10^6) s-1

= 6.957*10^-28 J

Answer: 6.957*10^-28 J

3)

frequency = 836.4 MHz = 8.364*10^8 Hz

we have below equation to be used

E = h*f

=(6.626*10^-34 J.s)*(8.364*10^8) s-1

= 5.542*10^-25 J

Answer: 5.542*10^-25 J