if 38.03 ml of 0.08289 M hydrochloric acid requires 21.33 ml of the NaOH solution to reach the endpoint, what is the molarity of the NaOH solution?
Balanced acid base neutrilisation reaction is
HCl + NaOH NaCl + H2O
no. of mole = molarity X volume of solution in liter
28.03 ml = 0.02803 liter
no. of mole of HCl = 0.08289 X 0.02803 = 0.0023234 mole
According to balanced reaction 1 mole HCl required 1 mole of NaOH therefore to neutrilize 0.0023234 mole of HCl required NaOH = 0.0023234 mole of NaOH
molarity = no. of mole/volume of solution in liter
21.33 ml = 0.02133 liter
molarity of NaOH = 0.0023234/0.02133 = 0.1089 M
Molarity of NaOH = 0.1089 M
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