Question

2. Toxic chromate can be precipitated from an aqueous solution by bubbling SO2(g) through the solution....

2. Toxic chromate can be precipitated from an aqueous solution by bubbling SO2(g) through the solution. How many grams of SO2 are required to treat 1.0 x 10^8 L of 0.000100 M CR+3?

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Answer #1

2CrO4^2- (aq) + 3SO2(g) + 4H^+ (aq) -------------> Cr2(SO4)3(s) + 2H2O

no of moles of Cr^3+ = molarity * volume in L

                                    = 0.0001*1*10^8   = 10000moles

2mole of Cr^3+ react with 3 moles of So2

10000 moles of Cr^3+ react with = 3*10000/2   = 15000 moles of So2

mass of So2 = no of moles * gram molar mass

                      = 15000*64    = 960000g of So2

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