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Given reaction is Fe(s) + HCl(aq) ------> HFeCl4(aq) + H2(g)
Oxidation half reaction is : Fe(s) ------> HFeCl4(aq)
Reduction half reaction is : HCl(aq) ------> H2(g)
The balanced reaction is obtained as follows:
Fe(s) + HCl(aq) ------> HFeCl4(aq) + H2(g)
Balance Cl atoms
Fe(s) + 4HCl(aq) ------> HFeCl4(aq) + H2(g)
Balance H atoms Fe(s) + 4HCl(aq) ------> HFeCl4(aq) + (3/2) H2(g)
OR 2Fe(s) + 8HCl(aq) ------> 2HFeCl4(aq) + 3H2(g)
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