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Balance the following redox reaction Fe(s) + HCl(aq) -> HFeCl4(aq) + H2(g)

Balance the following redox reaction
Fe(s) + HCl(aq) -> HFeCl4(aq) + H2(g)
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Answer #1

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Given reaction is Fe(s) + HCl(aq) ------> HFeCl4(aq) + H2(g)

Oxidation half reaction is :  Fe(s) ------> HFeCl4(aq)

Reduction half reaction is : HCl(aq) ------> H2(g)

The balanced reaction is obtained as follows:

Fe(s) + HCl(aq) ------> HFeCl4(aq) + H2(g)

Balance Cl atoms

Fe(s) + 4HCl(aq) ------> HFeCl4(aq) + H2(g)

Balance H atoms Fe(s) + 4HCl(aq) ------> HFeCl4(aq) + (3/2) H2(g)

OR 2Fe(s) + 8HCl(aq) ------> 2HFeCl4(aq) + 3H2(g)

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