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Hello

Hello

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Answer #1

Let be monoprotic acid be HA. It will dissociate as follows :

HA -------> H+   +   A-

1 moles of H+ is formed from 1 mole of acid

Molar concentration of the acid = Molarity = moles/ L of solution

number of moles of acid present = 0.003g/ 128 g mol-1 = 2.34 *10-5

pH = - log [H+] = 4.98

[H+] = 1.05 *10-5 M

[H+] = [A-] = 1.05 *10-5

Keq = [H+][A-]/[HA]

       = (1.05 *10-5)2 / 2.34 *10-5

         = 0.47 *10-5

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