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The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 514 mol of...

The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 514 mol of octane combusts, what volume of carbon dioxide is produced at 38.0 ∘C and 0.995 atm?

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